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15x^2+11x=12
We move all terms to the left:
15x^2+11x-(12)=0
a = 15; b = 11; c = -12;
Δ = b2-4ac
Δ = 112-4·15·(-12)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-29}{2*15}=\frac{-40}{30} =-1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+29}{2*15}=\frac{18}{30} =3/5 $
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